Tabel al derivatelor unor funcţii elementare si reguli de derivare pentru teza la matematica si examenul de bacalaureat la matematica
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litere de A si M backtrackingMetoda Backtracking Sa se genereze toate sirurile de lungime n, formate numai din literele A si M, siruri care sa nu... Read more 17 Feb 2012 Hits:27 backtracking probleme rezolvate atestat informatica c++ p2SUBIECTE SI REZOLVARI C++ PENTRU EXAMENUL DE ATESTAT LA INFORMATICĂ 25.Se citeşte de la tastatura un număr natural nenul n care... Read more 07 Feb 2012 Hits:319 atestat Varianta 30 bacalaureat informatica 2007Varianta 30 bacalaureat informatica 2007Cerinte si rezolvari {pdf=pdf/bacalaureat2007/varianta_030.pdf|600|600} Rezolvari probleme 1) #include<fstream.h>ofstream g("bac.txt");int a[101][101],i,j,n;void fct(){ for(i=1;i<=n;i++) ... Read more 31 Ian 2012 Hits:59 bacalaureat 2007 Varianta 29 bacalaureat informatica 2007Varianta 29 bacalaureat informatica 2007Cerinte si rezolvari {pdf=pdf/bacalaureat2007/varianta_029.pdf|600|600} Rezolvari probleme 1) #include<fstream.h>ofstream g("bac.txt");void main(){ int n; cin>>n; for(int i=1;i<=n;i++) g<<i*3<<" ";} 2) #include<iostream.h>long n;void f(){ cin>>n; int i=0,a[10]; while(n) { i++; a[i]=n%10; n/=10; } int x=a[1]; int y=a[2]; int ok=1; for(int j=3;j<=i;j++) { if(j%2==1) if(a[j]!=x) ok=0; if(j%2==0) if(a[j]!=y) ok=0; } if(ok) cout<<"DA"; else cout<<"NU";}void... Read more 31 Ian 2012 Hits:60 bacalaureat 2007 Varianta 28 bacalaureat informatica 2007Varianta 28 bacalaureat informatica 2007Cerinte si rezolvari {pdf=pdf/bacalaureat2007/varianta_028.pdf|600|600} Rezolvari 1) #include<iostream.h>#include<math.h>long a,v[11],i,j,ok=1;void fct(){ int x=a%10; v[1]=x; int y=x; for(i=2;i<=10;i++) { y=y*x; v[i]=y%10; if(v[i]==v[1]) i=11; else ok++; }}void main(){ cin>>a; fct(); int n=2007%ok; cout<<v[n];} 2) #include<iostream.h>int a[101][101],i,j,n;void fct(){ for(j=1;j<=n;j++) a[1][j]=j; for(i=2;i<=n;i++) for(j=1;j<=n;j++) { if(a[i-1][j+1]==0) a[i][j]=a[i-1][n-j+1]; else a[i][j]=a[i-1][j+1]; }}void afis(){ for(i=1;i<=n;i++) { for(j=1;j<=n;j++) cout<<a[i][j]<<" "; cout<<endl; }}void main(){ cin>>n; fct(); afis();} 3) #include<iostream.h>#include<math.h>long k;int panta(long... Read more 31 Ian 2012 Hits:38 bacalaureat 2007 Varianta 27 bacalaureat informatica 2007Varianta 27 bacalaureat informatica 2007Cerinte si rezolvari {pdf=pdf/bacalaureat2007/varianta_027.pdf|600|600} Rezolvari 1) #include<iostream.h>int n,i;void main(){ cin>>n; for(i=1;i<=n;i++) cout<<i*10<<" ";} 2) #include<iostream.h>#include<string.h>char a[101],b[101];int n;int aparitii(char s[101],char x){ int ok=0; for(int i=0;i<strlen(s);i++) if(s[i]==x) ok++; return ok;}void main(){ cin>>a; cin>>b; int ok=1; for(int... Read more 31 Ian 2012 Hits:33 bacalaureat 2007 Varianta 26 bacalaureat informatica 2007Varianta 26 bacalaureat informatica 2007Cerinte si rezolvari {pdf=pdf/bacalaureat2007/varianta_026.pdf|600|600} Rezolvari 1) #include<iostream.h>#include<math.h>void main(){ float a; int x,y; cin>>a; cout<<floor(a)<<" "; if(ceil(a)==a) cout<<ceil(a)+1; else cout<<ceil(a);} 2) #include<iostream.h>#include<math.h>int A[11][11];void citire(){ for(int i=1;i<=10;i++) for(int j=1;j<=10;j++) cin>>A[i][j];}int maxim(int A[11][11],int i1,int i2){ int max=0; for(int... Read more 31 Ian 2012 Hits:32 bacalaureat 2007 Varianta 25 bacalaureat informatica 2007Varianta 25 bacalaureat informatica 2007Cerinte si rezolvari {pdf=pdf/bacalaureat2007/varianta_025.pdf|600|600} Rezolvari 1) #include<fstream.h>ifstream f("bac.txt");#include<math.h>int i,n;float min;struct vect { float x,y;};vect v[100];void citire(){ f>>n; for(i=1;i<=n;i++) f>>v[i].x>>v[i].y; }void f1(){ min=sqrt(pow(v[1].x,2)+pow(v[1].y,2)); for(i=2;i<=n;i++) if(sqrt(pow(v[i].x,2)+pow(v[i].y,2)) < min) { min=sqrt(pow(v[i].x,2)+pow(v[i].y,2)); }}void f2(){ for(i=1;i<=n;i++) { float d... Read more 31 Ian 2012 Hits:33 bacalaureat 2007 |
formule matematice derivate